Display part of the input using shell script

Question

How can I get the output below using shell commands?

Input as below:

Nexus-test-1.12.3
Producer-1.13.3
Testing-one-word-1.12

Output should be

Nexus-test
Producer
Testing-one-word

Remove everything after and including the first `.` – William Pursell Jan 28 '20 at 15:57 — William Pursell, Jan 28 '20 at 15:57
`sed` would be a good choice. – William Pursell Jan 28 '20 at 15:59 — William Pursell, Jan 28 '20 at 15:59
Sorry there is a change in question – Anusha M Jan 28 '20 at 17:51 — Anusha M, Jan 28 '20 at 17:51

score 1 · Answer 1 · answered Jan 28 '20 at 16:03

1

I really struggle with whether or not to answer this, because it's incredibly trivial and it appears that zero effort has been made to figure it out. But....just do:

cut -d . -f 1

answered Jan 28 '20 at 16:03

William Pursell

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score 1 · Answer 2 · answered Jan 28 '20 at 16:04

1

There are many ways to do it, hope you can do a search first.

awk:

awk -F'.' '{$0=$1}7'

sed:

sed 's/[.]*//'

grep:

grep -Po '^[^.]*'

answered Jan 28 '20 at 16:04

Kent

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Sorry, There is a change in question – Anusha M Jan 28 '20 at 17:50

Display part of the input using shell script

2 Answers2

awk:

sed:

grep: