I need accept the following url in my flask restplus app: .../app/u1=abc;u2=222;u3=xx;u4=jjj, all of them can be optional How I need to define my route?
@api.route('/app/u1=<u1>;u2=<u2>;u3=<u3>;u4=<u4>')
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if you want to make it optional you should take it as the query parameter – Mohammad Aarif Jan 27 '20 at 11:39
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URL parameters are not separated by semicolons. Are you sure this is exactly what you have? – Harshal Parekh Jan 27 '20 at 14:06
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@HarshalParekh yes, it exactly what I have. – Boris Becker Jan 27 '20 at 15:38