How can I exclude a property from a lombok builder only if the property is null

Question

I have a user model class that looks like:

@JsonSerialize
@Getter
@Setter
@FieldDefaults(level = AccessLevel.PRIVATE)
@Builder
public class User {
    @Default
    String _dn = BASE_USER_DN;
    @Default
    String[] objectClass = {"top", "person", "organizationalPerson", "inetOrgPerson", "companyUser"};
    @Default
    String[] cn = {"user205"};
    @Default
    String[] sn = {"Dynamic2"};
    @Default
    String[] username = {"LindaDynamic2"};
}

Now I'd like to generate a user object that omits null fields so:

userBody = User.builder().cn(null).build();

would create an object without a cn property or if I added a field without a default and it wasn't set on the builder it would be omitted.

Is this possible?

you want to exclude during serialization ? – Ryuzaki L Jan 16 '20 at 17:10 — Ryuzaki L, Jan 16 '20 at 17:10

score 10 · Accepted Answer · answered Jan 16 '20 at 17:16

10

Add following annotation if you want to exclude during serialization:

@JsonInclude(Include.NON_NULL)

answered Jan 16 '20 at 17:16

Chetan Komakula

369
2
5

so simple and yet so brilliant – amadain Jan 16 '20 at 17:51
1

Note: this is a `jackson` annotation. It is unrelated to Lombok. It can be added at the class level, method level, field level, etc. – payne Sep 24 '21 at 22:58
Way better than using that old `@JsonIgnore` annotation, right? – djangofan Oct 13 '21 at 18:16

How can I exclude a property from a lombok builder only if the property is null

1 Answers1

Linked