How to make the command interpreter aware of the newly created target

Question

I want to use LLDB as a python library as described here https://lldb.llvm.org/use/python-reference.html#using-the-lldb-py-module-in-python.

After creating a target with

debugger = lldb.SBDebugger.Create()
target = debugger.CreateTargetWithFileAndArch(path_to_executable, lldb.LLDB_ARCH_DEFAULT)

and getting the command interpreter with

interpreter = debugger.GetCommandInterpreter()

I try to start the target with

ret = llldb.SBCommandReturnObject()
interpreter.HandleCommand('/r', ret)

I get error: invalid target, create a target using the 'target create' command. I also tried to set the selected target with debugger.SetSelectedTarget(target), but it didn't work either. Running file <path_to_target> in the command handler works as expected.

Is there a way to create a target in python and run commands in the interpreter against it?

score 0 · Answer 1 · answered Jan 12 '20 at 18:23

0

Apparently, debugger.CreateTargetWithFileAndArch doesn't return valid targets, which you can see by doing bool(target). Use

target = debugger.CreateTargetWithFileAndArch(path_to_executable, lldb.LLDB_ARCH_DEFAULT)
debugger.SetSelectedTarget(target)

answered Jan 12 '20 at 18:23

Dimitri Vorona

450
3
13

If target is not valid, then how `debugger.SetSelectedTarget(target)` could help? – Dmitry Mikushin Jul 29 '20 at 12:05

score 0 · Answer 2 · answered Jul 29 '20 at 16:08

Apparently, lldb.LLDB_ARCH_DEFAULT does not work by some reason on MacOS. So I've replaced it with an explicit name:

target = debugger.CreateTargetWithFileAndArch(exe, "x86_64-apple-macosx10.15.0")

followed by:

assert target

which should help to avoid unexpectedly empty target.

How to make the command interpreter aware of the newly created target

2 Answers2