What is the difference between int [5] and int ()[5] in C?

Question

I am trying to understand the difference between int *[5] and int (*)[5] and my simple code is as below.

int main()
{
    int a[5] = {10,11,12,13,14};
    int *ptr[5];
    ptr = &a;
}

Maybe that would help you: https://stackoverflow.com/questions/1893013/complex-declarations — dragosht, Jan 08 '20 at 07:36

score 1 · Accepted Answer · edited Jan 08 '20 at 08:44

1

int a[5] - a is an array of 5 int.

int (*a)[5] - a is a pointer to an array of 5 int.

int a[5][4] - a is an mulitdimensional array with 5 dimensions of 4 int.

int *a[5] - a is an array of 5 int pointers.

edited Jan 08 '20 at 08:44

answered Jan 08 '20 at 07:37

Julian

`mulitdimensional array with 5 dimensions of 4 int` does not make sense. `a` is a 5×4 array of `int`s, simply. Or, precisely, `a` is an array of 5 objects, each of which is an array of 4 `int`s. – Lxer Lx Jan 08 '20 at 10:27

What is the difference between int *[5] and int (*)[5] in C?