'SQLite.swift/SQLCipher' error: ambiguous use of 'SQLITE_DETERMINISTIC'

Question

I'm using SQLite.swift and SQLCipher via cocoapods.

I get the error ambiguous use of 'SQLITE_DETERMINISTIC' in the SQLite.swift file: Connection.swift fails at line 590. Snippet is show below.

        var flags = SQLITE_UTF8
        #if !os(Linux)
        if deterministic {
            flags |= SQLITE_DETERMINISTIC
        }
        #endif

I can fix this by unlocking the pod file and replace 'SQLITE_DETERMINISTIC' with 'SQLCipher.SQLITE_DETERMINISTIC' or 'SQLite.SQLITE_DETERMINISTIC'. But this is bad for lots of reasons.

Steps to reproduce:

Using Xcode 11.3
Create a new project (Single View App is fine)
Create a Podfile (example below)
Run 'pod install'
Open the Workspace and compile
Build fails with error

Example Podfile:

use_frameworks!


target 'TestSQLite' do
    pod 'SQLite.swift/SQLCipher', '~> 0.12.2' # with SQLCipher
end

Any help would be appreciated.

score 2 · Accepted Answer · answered Jan 08 '20 at 05:15

2

SQLite.swift version 0.12.2 and you did not specify SQLCipher version. Please check SQLCipher version which may be 4.3.0 in Podfile.lock file. In this case, set SQLCipher version to 4.2.0. Clean and build the project. It will work. You can update pods

pod 'SQLCipher', '~>4.2.0'

pod 'SQLite.swift/SQLCipher', '~>0.12.0'

Run following commands in command line

pod deintegrate

pod install

Thank you

answered Jan 08 '20 at 05:15

Abdullah Al Mamun

54
4

Thanks! That's the ticket. – Jeff Miller Jan 09 '20 at 14:55
Okay but this solution is only saying to rollback the version. This doesn't solve for staying on the current version 4.3.0. – casperson Feb 06 '20 at 19:33
With Xcode 12.4 the above solution does not work anymore it returns in SCLCipher/Connection.Swift line 590 an error: Ambiguous use of 'SQLITE_DETERMINISTIC' – ReaLity Mar 02 '21 at 17:03

'SQLite.swift/SQLCipher' error: ambiguous use of 'SQLITE_DETERMINISTIC'

1 Answers1