How to make a button that dismisses a view presented using UIHostingController/SwiftUI?

Question

I have a fairly extensive project that I started with UIKit and now I've decided to use SwiftUI to make some simple form pages, but I need to make a button in SwiftUI to dismiss the current view which is presented with the following code:

   func goToSchedule() {
        let vc = UIHostingController(rootView: ScheduleView())
        if let topController = UIApplication.topViewController() {
            topController.present(vc, animated: true, completion: nil)
        }
    }

score 3 · Answer 1 · answered Jan 05 '20 at 05:12

3

You can dismiss it by holding a reference to it. So hold vc in more public scope and dismiss it when you need to.

var vc: UIViewController

or something like this:

if let topController = UIApplication.topViewController() {
    topController.presentedViewController?.dismiss(animated: true)
}

answered Jan 05 '20 at 05:12

Mojtaba Hosseini

95,414
31
268
278

I want to dismiss it using a button inside my SwiftUI view. – Watermamal Jan 05 '20 at 05:28
No difference, put the code in a function and call it where you need – Mojtaba Hosseini Jan 05 '20 at 05:37
Thanks, it works. For some reason I thought this method wouldn't work with SwiftUI, the only thing here is in my specific case it has to be topController.dismiss(), presentedViewController returns nil. – Watermamal Jan 05 '20 at 15:15

score 1 · Accepted Answer · answered Jan 05 '20 at 06:50

If I correctly understood code snapshot then .topViewController() will be presented UIHostingViewConroller when ScheduleView shown, so it should inside it like

var body: some View {
    // ...
    // somewhere ...

    Button("Close") {
        if let topController = UIApplication.topViewController() {
            topController.dismiss(animated: true)
        }
    }
}

How to make a button that dismisses a view presented using UIHostingController/SwiftUI?

2 Answers2