SAXParser with local XML file

Question

I've read several topic on how to read local XML file.

Most of them are using openRawResource(). However it's much more slower compared to getXML().

I wanted to use getXML for my project, it's there any way to use getXML with XMLReader.parse(), as SAX InputSource does not accept XmlResourceParser as parameter.

Edit: btw, when do the startElement endElement will be called? Is it right after XMLReader.parse? Is it possible to restart the parsing from the top when I read a certain value of attributes?

Thank you very much

score 2 · Answer 1 · edited May 10 '11 at 12:06

try {
            SAXParserFactory factory = SAXParserFactory.newInstance();
            SAXParser parser = factory.newSAXParser();
            XMLReader reader = parser.getXMLReader();
            MyXMLHandler myXMLHandler = new MyXMLHandler(getApplicationContext());
            reader.setContentHandler(myXMLHandler);
            reader.parse(new InputSource(getAssets().open("Getalloffersbyzipcoderesponse_xml.xml")));
        //  listView.setAdapter(new EventListAdapter(getApplicationContext(), 0, myXMLHandler.getEventList()));
            listView.setAdapter(new OffersListAdapter(getApplicationContext(), 0, myXMLHandler.getOffersList()));
        } catch (ParserConfigurationException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (SAXException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

Tanmay Mandal · Accepted Answer · 2011-05-12T05:35:25.323

1

You can use it(assume that you are keeping your xml in assets folder)

 InputStream response=context.getAssets().open("your.xml");

and then

  Xml.parse(response, Xml.Encoding.UTF_8,rootElement.getContentHandler());

edited May 12 '11 at 05:35

answered May 10 '11 at 10:27

Tanmay Mandal

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Apparently I could not access the xml if I use the path "assets/your.xml" but it works if it's "your.xml" – Yaobin Then May 12 '11 at 05:14
Thanks for showing me the wrong part of the code.Fixed it.It was a copy paste error. – Tanmay Mandal May 12 '11 at 05:36

score 0 · Answer 3 · answered May 10 '11 at 10:19

0

If you want to use the 'getXML()'-function, you can check out this tutorial, whic show's how to use the 'XmlResourceParser'-Interface: Link

Anothet way would be if you put the XML files in the 'openRawResource'-method, which returns an 'InputStream' on a given Resource ID, which you can then pass to the normal 'SAXParser'.

answered May 10 '11 at 10:19

Lukas Knuth

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I've seen many post telling that openRawResource is 10x slower than getXML, that's why I put this question up. Checking on the former link you provided :) – Yaobin Then May 10 '11 at 10:23
I'm not sure if there is any difference but you can try and see wich one is faster... – Lukas Knuth May 10 '11 at 10:25

SAXParser with local XML file

3 Answers3

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