Say I have a dataframe of tens of columns, and my custom function needs each one of these columns plus a number in a vector to give me the desired output. After being done with all that, I need to generate new column names based on the original column names in the dataframe. How to accomplish this using the tidyverse
, instead of for
loops or other solutions in base R
.
MWE
structure(list(col1 = c(36.0520583373645, 37.9423749063706, 33.6806634587719,
34.031649012457, 29.5448679963449, NA, 34.7576769718877, 30.484217745574,
32.9849083643022, 27.4081694831058, 35.8624919654559, 35.0284347997991,
NA, 32.112605893241, 27.819354948082, 35.6499532124921, 35.0265642403216,
32.4006569441297, 30.3698557864842, 31.8229364456928, 34.3715903109276
), col2 = c(32.9691195198199, 35.6643664156284, 33.8748732989736,
34.5436311813644, 33.2228201914256, 38.7621696867191, 34.8399804318992,
32.9063078995457, 35.7391166214367, 32.7217251282669, 36.3039268989853,
35.9607654868559, 33.1385915196435, 34.7987649028199, 33.7100463668523,
34.7773403671057, 35.8592997980752, 33.8537127786535, 31.9106243803505,
39.3099469314882, 35.1849826815196), col3 = c(33.272278716963,
NA, 31.8594920410129, 33.1695042551974, 29.3800694974438, 35.1504378875245,
34.0771487001433, 29.0162879030415, 30.6960024888799, 29.5542117965184,
34.3726321365982, 36.0602274148362, 33.1207772548047, 31.5506876209822,
28.8649303491974, 33.4598790144265, 30.5573454464747, 31.6026723913051,
30.4716061556625, 33.009463000301, 30.846230953425)), row.names = c(NA,
-21L), class = "data.frame")
save above in a file, and then use example <- dget(file.choose())
to read the above dataframe.
Code
y <- c (2, 1, 1.5)
customfun <- function(x, y){
n <- log (x) * y
print (n)
}
df <- example %>%
dplyr::mutate(col1.log = customfun (col1, y = y[1])) %>%
dplyr::mutate(col2.log = customfun (col2, y = y[2])) %>%
dplyr::mutate(col3.log = customfun (col3, y = y[3]))
Question
Imagine I have tens of these columns not only 3 as in the MWE, how to generate the new ones dynamically using the tidyverse?