I'm using this code to convert from an XElement to OpenXmlElement
internal static OpenXmlElement ToOpenXml(this XElement xel)
{
using (var sw = new StreamWriter(new MemoryStream()))
{
sw.Write(xel.ToString());
sw.Flush();
sw.BaseStream.Seek(0, SeekOrigin.Begin);
var re = OpenXmlReader.Create(sw.BaseStream);
re.Read();
var oxe = re.LoadCurrentElement();
re.Close();
return oxe;
}
}
Before the conversion I have an XElement
<w:ind w:firstLine="0" w:left="0" w:right="0"/>
After the conversion it looks like this
<w:ind w:firstLine="0" w:end="0" w:start="0"/>
This element then fails OpenXml validation using the following
var v = new OpenXmlValidator();
var errs = v.Validate(doc);
With the errors being reported:
Description="The 'http://schemas.openxmlformats.org/wordprocessingml/2006/main:start' attribute is not declared."
Description="The 'http://schemas.openxmlformats.org/wordprocessingml/2006/main:end' attribute is not declared."
Do I need to do other things to add these attributes to the schema or do I need to find a new way to convert from XElement to OpenXml?
I'm using the nuget package DocumentFormat.OpenXml ver 2.9.1 (the latest).
EDIT: Looking at the OpenXml standard, it seems that both left/start and right/end should be recognised which would point to the OpenXmlValidator not being quite correct. Presumably I can just ignore those validation errors then?
Many thx