How to create own class App without intersecion with Kivy App?

Asked Dec 13 '19 at 08:23

Active Dec 13 '19 at 08:23

Viewed 11 times

I need to create a new class with name App and wrap default Kivy App method run(), but Kivy already has this name. What I tried to do:

from kivy.app import App as KvApp


class SportApp(KvApp):
    def build(self):
        # here it builds

# my class
class App:
    def start_app(self):
        SportApp().run()

if __name__ == '__main__':
    App.start_app()

App.start_app()

TypeError: start_app() missing 1 required positional argument: 'self'

edited Jun 20 '20 at 09:12

Community

asked Dec 13 '19 at 08:23

Pavel Antspovich

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change `def start_app(self)` to `@staticmethod` `def start_app()` or change `App.start_app()` to `App().start_app()` – eyllanesc Dec 13 '19 at 08:31
@eyllanesc, yes, thanks – Pavel Antspovich Dec 13 '19 at 08:34
To use an instance method it is logical that you need an instance, isn't it logical for you? – eyllanesc Dec 13 '19 at 08:36
@eyllanesc, yep, just understood it. It's mine inattention – Pavel Antspovich Dec 13 '19 at 08:37

How to create own class App without intersecion with Kivy App?

0 Answers0