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    ClientConfiguration cfg = new ClientConfiguration().setAddresses("127.0.0.1:10800");

    try (IgniteClient igniteClient = Ignition.startClient(cfg)) {

        System.out.println(">>> Thin client put-get example started.");

        final String CACHE_NAME = "put-get-example";

        ClientCache<Integer, Object> cache = igniteClient.getOrCreateCache(CACHE_NAME);

        Person p = new Person();

        //put
        HashMap<Integer, Person> hm = new HashMap<Integer, Person>();
        hm.put(1, p);
        cache.put(1, hm);

        //get
        HashMap<Integer, Person> map = (HashMap<Integer, Person>)cache.get(1);
        Person p2 = map.get(1);

        System.out.format(">>> Loaded [%s] from the cache.\n",p2);

    }
    catch (ClientException e) {
        System.err.println(e.getMessage());
        e.printStackTrace();
    }
    catch (Exception e) {
        System.err.format("Unexpected failure: %s\n", e);
        e.printStackTrace();
    }

I use the thin client of apache-ignite.

I Create a hashmap and put the Person class(org.apache.ignite.examples.model.Person) object into it.

And when I take it out of the hashmap, I get the following exceptions:

> java.lang.ClassCastException:
> org.apache.enite.internal.binary.BinaryObjectImpl cannot be cast to
> org.apache.engite.examples.model.Person.

An exception is given in the code below.

Person p2 = map.get(1);

However, there is no exception if I modify the code as follows:

BinaryObject bo = (BinaryObject) map.get(1);

Person p2 = bo.deserialize();

I don't think that's necessary. Is there another solution?

Ahmad
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이평범
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    Do you really want to put a HashMap as a cache value instead of a plain Person? Consider: Person p = new Person(); cache.put(1, p); – Alexandr Shapkin Dec 12 '19 at 09:35

1 Answers1

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Change client Cache definition 

ClientCache<Integer, Person> cache = igniteClient.getOrCreateCache(CACHE_NAME)
Ashok v
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