Treat every whitespaces as the same character in Regex

Question

I made a regex to highlight keywords found in a text by another tool.

new RegExp(highlightedKeywords.map(v => `\\b${v}\\b`).join('|') || /.^/, 'gi'), match => `<mark>${match}</mark>`)

I would like to make this regex treat every whitespaces as the same because the tool who extract keywords from the text convert every whitespace as space, so for example I have a keyword "the cat" not found because the actual text is "the\ncat".

I don't want to ignore whitespaces because "the cat" should not match "thecat" but I would like to match "the\tcat" or even "the\n \tcat"

But you may want to provide sample data for `highlightedkeywords` and desired output for others to give you stronger feedback on the best approach for you. — pwilcox, Dec 09 '19 at 15:10
Answer is [here](https://stackoverflow.com/a/48236101/3832970). — Wiktor Stribiżew, Dec 09 '19 at 20:20

score 0 · Answer 1 · answered Dec 09 '19 at 15:28

0

Answer found thanks to pwilcox : "You're looking for \s"

new RegExp(highlightedKeywords.map(v => `\\b${v.replace(/\s/g, '\\s')}\\b`).join('|') || /.^/, 'gi')`

I replace every whitespace in the keywords by \s

answered Dec 09 '19 at 15:28

Gatoyu

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Treat every whitespaces as the same character in Regex

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