Is it possible to export some of the class template instances, while leaving to a library's user the ability of generating other specializations of a given class template (when compiling the executable).
Given I have a public header
// public.h
#pragma once
#ifndef DLL_BUILD
#define API __declspec(dllimport)
#else
#define API __declspec(dllexport)
#endif // !DLL_BUILD
#include <type_traits>
// dummy to generate .lib
struct API dummy
{
void be_dummy();
};
template <class T>
struct Foo
{
static T Sum(T a, T b)
{
static_assert(std::is_fundamental_v<T>);
return a + b;
}
};
With this way of declaring class template Foo
every instantiation will happen inside the user's executable.
However, if I define Foo
as dllexport/dllimport
using API
macro, every specialization of Foo
which has not been explicitly instantiated inside the dll, will fail to link.
// impl.cpp - dll
#include "public.h"
void dummy::be_dummy()
{
volatile int a = 0;
return;
}
template API struct Foo<int>;
///////////////////////////////////////////
// main.cpp - executable
#include "public.h"
#include <iostream>
int main()
{
dummy().be_dummy();
// std::cout << Foo<double>().Sum(4.12, 3.18) << std::endl; // Unresolved external symbol
std::cout << Foo<int>().Sum(60, 9) << std::endl; // executed within the dll
return 0;
}
So, is it possible to force the compiler to link against an existing class template instance when one has been exported, and to generate another that has not.
UPDATE
I found a solution, see my answer below. I leave the old update just in case anybody will find such usage of SFINAE helpful.
UPDATE OLD
I found one cumbersome solution involving SFINAE, but it results in defining a class template twice, therefore is very error prone. I don't know if it can be wrapped up with macro in a manner that will make it possible to write it only once.
// public.h
#pragma once
#ifndef DLL_BUILD
#define API __declspec(dllimport)
#else
#define API __declspec(dllexport)
#endif // !DLL_BUILD
#include <type_traits>
namespace templ_export
{
template <class T>
struct is_exported : std::false_type {};
// this can be placed to a separated header (i.e. Exported.hpp)
template <> struct is_exported<int> : std::true_type {};
template <class T>
struct API FooExported
{
static T Sum(T a, T b)
{
//static_assert(std::is_fundamental_v<T>);
return a + b;
}
};
template <class T>
struct FooNotExported
{
static T Sum(T a, T b)
{
//static_assert(std::is_fundamental_v<T>);
return a + b;
}
};
template <class T, bool = templ_export::is_exported<T>()>
struct GetFooExported
{
using type = FooNotExported<T>;
};
template <class T>
struct GetFooExported<T, true>
{
using type = FooExported<T>;
};
}
template <class T>
using Foo = typename templ_export::GetFooExported<T>::type;
/////////////////////////////////
// impl.cpp
#include "public.h"
void dummy::be_dummy()
{
volatile int a = 0;
return;
}
template struct API templ_export::FooExported<int>;