Output number of iterations for Newton Method using Scipy

Question

I would like to know how I can output the number of iterations when finding the root using Newtons method. I am calculating the root automatically using Scipy, so I wanted to know if there is a way of knowing how many iterations it took:

from spicy.optimize import newton
from math import *

f = lambda x : x**2 - sin(x)
ans = newton(f, 1, tol = 1.0E-8, maxiter = 100)
print(round(ans, 8))

score 1 · Answer 1 · answered Nov 29 '19 at 06:20

1

Spicy is a cool name for scipy. :)

Jokes aside, you simply need to include full_output=True in your call to newton (see the doc for more detail). Executing your code, I got this output by printing ans:

(0.8767262153950625,       converged: True
           flag: 'converged'
 function_calls: 7
     iterations: 6
           root: 0.8767262153950625)

answered Nov 29 '19 at 06:20

Patol75

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Hahah. typed in the code and I didn't notice the typo. Thanks for the solution! – Prog101 Nov 29 '19 at 09:29
@Prog101 No worries. Please feel free to upvote and accept the answer. :) – Patol75 Nov 29 '19 at 11:48

Output number of iterations for Newton Method using Scipy

1 Answers1