I'm trying to set a rounded border to a button but the border of the button is not correct.
Code:
Button(action: {
print("sign up bin tapped")
}) {
Text("SIGN UP")
.frame(minWidth: 0, maxWidth: .infinity)
.font(.system(size: 18))
.padding()
.foregroundColor(.white)
}
.border(Color.white, width: 2)
.cornerRadius(25)
Output:
As you can see the border at corner are cut-off.
Any suggestion what am I doing wrong?
Instead of setting the cornerRadius to the Button use an overlay for the inside View:
Edit: If you have a background for the button you also need to apply the cornerRadius to the background.
Button(action: {
print("sign up bin tapped")
}) {
Text("SIGN UP")
.frame(minWidth: 0, maxWidth: .infinity)
.font(.system(size: 18))
.padding()
.foregroundColor(.white)
.overlay(
RoundedRectangle(cornerRadius: 25)
.stroke(Color.white, lineWidth: 2)
)
}
.background(Color.yellow) // If you have this
.cornerRadius(25) // You also need the cornerRadius here
None of the examples worked for buttons with both dark and white background colors as well as none of them had press state updates, so I built this LargeButton view that you can see below. Hope this helps, should be pretty simple to use!
// White button with green border.
LargeButton(title: "Invite a Friend",
backgroundColor: Color.white,
foregroundColor: Color.green) {
print("Hello World")
}
// Yellow button without a border
LargeButton(title: "Invite a Friend",
backgroundColor: Color.yellow) {
print("Hello World")
}
struct LargeButtonStyle: ButtonStyle {
let backgroundColor: Color
let foregroundColor: Color
let isDisabled: Bool
func makeBody(configuration: Self.Configuration) -> some View {
let currentForegroundColor = isDisabled || configuration.isPressed ? foregroundColor.opacity(0.3) : foregroundColor
return configuration.label
.padding()
.foregroundColor(currentForegroundColor)
.background(isDisabled || configuration.isPressed ? backgroundColor.opacity(0.3) : backgroundColor)
// This is the key part, we are using both an overlay as well as cornerRadius
.cornerRadius(6)
.overlay(
RoundedRectangle(cornerRadius: 6)
.stroke(currentForegroundColor, lineWidth: 1)
)
.padding([.top, .bottom], 10)
.font(Font.system(size: 19, weight: .semibold))
}
}
struct LargeButton: View {
private static let buttonHorizontalMargins: CGFloat = 20
var backgroundColor: Color
var foregroundColor: Color
private let title: String
private let action: () -> Void
// It would be nice to make this into a binding.
private let disabled: Bool
init(title: String,
disabled: Bool = false,
backgroundColor: Color = Color.green,
foregroundColor: Color = Color.white,
action: @escaping () -> Void) {
self.backgroundColor = backgroundColor
self.foregroundColor = foregroundColor
self.title = title
self.action = action
self.disabled = disabled
}
var body: some View {
HStack {
Spacer(minLength: LargeButton.buttonHorizontalMargins)
Button(action:self.action) {
Text(self.title)
.frame(maxWidth:.infinity)
}
.buttonStyle(LargeButtonStyle(backgroundColor: backgroundColor,
foregroundColor: foregroundColor,
isDisabled: disabled))
.disabled(self.disabled)
Spacer(minLength: LargeButton.buttonHorizontalMargins)
}
.frame(maxWidth:.infinity)
}
}
.bordered modifier support in iOS 15+Buttons now have baked in border styling support using the .buttonStyle(.bordered) modifier. I would suggest using the corner radius Apple provides for these buttons for the best platform-specific styling. We can change the color to be consistent with the system styles for buttons and tint the background as well as text using the .tint modifier:
Button("Add") { ... }
.buttonStyle(.bordered)
.tint(.green)
You can make the tint color more prominent (bolder) using .borderedProminent and control the size using .controlSize:
Button("food") { ... }
.tint(.red)
.controlSize(.small) // .large, .medium or .small
.buttonStyle(.borderedProminent)
You can also use this modifier on parent Views of Buttons and toggle lighter color schemes using .accentColor in child Buttons:
ScrollView {
LazyVStack {
Button("Test Button 1") { ... }
.buttonStyle(.borderedProminent)
.keyboardShortcut(.defaultAction) // Tapping `Return` key actions this button
Button("Test Button 2") { ... }
.tint(.accentColor)
}
}
.buttonStyle(.bordered)
.controlSize(.large)
Apple for some reason doesn't like single-line bordered buttons which is why the .border() modifier was deprecated in Xcode 12. With this change, I suggest developers avoid creating single-line bordered buttons because they now are not preferred in Apple's Human Interface Guidelines. Using prominent buttons everywhere also violates HIG.
Extra NOTE: Apple's .bordered style provides the standard platform style across device types. In addition, the Button responds to Dark Mode dynamically and scales its size with Dynamic Type (native accessibility support).
Just add the cornerRadius argument:
.border(Color.white, width: 2, cornerRadius: 25)
using this simple extension:
extension View {
func border(_ color: Color, width: CGFloat, cornerRadius: CGFloat) -> some View {
overlay(RoundedRectangle(cornerRadius: cornerRadius).stroke(color, lineWidth: width))
}
}
Swift 5 & iOS 14 – Borders also react when pressed
struct PrimaryButtonStyle: ButtonStyle {
func makeBody(configuration: Configuration) -> some View {
configuration.label
.padding(5)
.foregroundColor(configuration.isPressed ? Color.red.opacity(0.5) : .red)
.overlay(
RoundedRectangle(cornerRadius: 8)
.stroke(configuration.isPressed ? Color.red.opacity(0.5) : .red, lineWidth: 1.5)
)
}
}
How to use
Button("Hide") {
print("tapped")
}.buttonStyle(PrimaryButtonStyle())
Swift version 5.6 You can use Button properties for example
Button(action: {
//define action
}) {
Image(systemName: "arrow.triangle.2.circlepath.circle.fill")
.imageScale(.large)
Text("Restart")
.font(.system(.title2))
}
.buttonStyle(.borderedProminent)
.buttonBorderShape(.capsule)
.controlSize(.large)
.buttonBorderShape(.roundedRectangle) //change bordershape see below
.buttonBorderShape(.roundedRectangle(radius: 4)) // see below
similarly you can change the buttonSytle and controlSize
Xcode 11.4.1
Button(action: self.action) {
Text("Button Name")
.font(.system(size: 15))
.fontWeight(.bold)
.foregroundColor(.white)
.padding(10)
.background(Color.darkGray)
.cornerRadius(10)
}
.buttonStyle(PlainButtonStyle())
There isn't a need to add an overlay. You can substitute padding modifier with frame modifier. The action is a non return method outside of the body variable.
Right specifically for @MinonWeerasinghe:
Button(action: self.action) {
Text("Button Name")
.font(.system(size: 15))
.fontWeight(.bold)
.foregroundColor(.black)
.padding(10)
.background(RoundedRectangle(cornerRadius: 10).stroke().foregroundColor(Color.red))
.cornerRadius(10)
}
.buttonStyle(PlainButtonStyle())
You can try this:
var body: some View {
ZStack {
Color.green
.edgesIgnoringSafeArea(.all)
HStack {
Button(action: {
print("sign up bin tapped")
}){
HStack {
Text("SIGN UP")
.font(.system(size: 18))
}
.frame(minWidth: 0, maxWidth: 300)
.padding()
.foregroundColor(.white)
.overlay(
RoundedRectangle(cornerRadius: 40)
.stroke(Color.white, lineWidth: 2)
)
}
}
}
}
I also did not set the maxWidth to .infinity because it means the button will fill the width of your container view.
The result will be :
Hope it helps :)
SwiftUI :- You can also try this!
Currently I added check on same button for different shapes. you can separate my code if you want.
// Global declaration
@State var isFollowed = false
Button {
// Toggle Your isFollowed with true and false
isFollowed = true
} label: {
Text(isFollowed ? "Following" : "Follow")
.padding(.horizontal, 10)
.padding(.vertical, 6)
.foregroundColor(.white)
.font(.custom(MyFont.GilroyBold, size: 13))
.background(
ZStack {
RoundedRectangle(
cornerRadius: 20,
style: .continuous
)
.fill(isFollowed ? .red : .clear)
RoundedRectangle(
cornerRadius: 20,
style: .continuous
)
.stroke(.red, lineWidth: 2)
}
)
}
eg. Like I need Follow and following button. On Follow button I shown corner rounds and only border. On Following button I shown corner rounds and background colour.
This worked for me
Button(action: {
print("Exit the onboarding")
}) {
HStack (spacing: 8) {
Text("NEXT")
.foregroundColor(Color("ColorAccentOppBlack"))
}
.padding(.horizontal, 16)
.padding(.vertical, 10)
.foregroundColor(Color("ColorYellowButton"))
.background(
Capsule().strokeBorder(Color("ColorYellowButton"), lineWidth: 1.25)
)
}
.accentColor(Color("ColorYellowButton"))
You should use Capsule. This is built-in into SwiftUI. It takes care of rounded corners. Full implementation is here https://redflowerinc.com/how-to-implement-rounded-corners-for-buttons-in-swiftui/
public struct ButtonStyling : ButtonStyle {
public var type: ButtonType
public init(type: ButtonType = .light) {
self.type = type
}
public func makeBody(configuration: Configuration) -> some View {
configuration.label.foregroundColor(Color.white)
.padding(EdgeInsets(top: 12,
leading: 12,
bottom: 12,
trailing: 12))
.background(AnyView(Capsule().fill(Color.purple)))
.overlay(RoundedRectangle(cornerRadius: 0).stroke(Color.gray, lineWidth: 0))
}
}
Wonder how to add button border with color gradient and corner radius Here's how..
Button(action: {self.isCreateAccountTapped = true},label: {Text("Create an Account")
.foregroundColor(Color("TextThemeColor36"))}
)
.frame(height: 44)
.frame(width: 166)
.background(Color.clear)
.cornerRadius(8)
.overlay(RoundedRectangle(cornerRadius: 10)
.stroke(LinearGradient(gradient: Gradient(colors: [Color("BtnGradientClr1"),Color("BtnGradientClr2"),Color("BtnGradientClr3")]), startPoint: .leading, endPoint: .trailing)))
