Possible Duplicate:
How do I get the bash command exit code from a Process run from within Java?
Hi, I have a program which is a simple decrypts another file using bash command ./nv0914 < nv0914.challenge where nv0914 is a unix executable file and nv0914.challenge is a text file used for decryption. Now when i am running it from bash and just after that if I run the command echo ${?} I am getting a value 0, which is good. But now I have to implement an attack and for that I need to get the exit value printed through a java program. I have this code as if now:
import java.io.*;
import java.util.*;
public class ExecBashCommand {
public static void main(String args[]) throws Exception {
Runtime runtime = Runtime.getRuntime();
Process process = runtime.exec("./nv0914 < nv0914.challenge");
/* InputStream is = process.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
BufferedReader br = new BufferedReader(isr);
String line;*/
System.out.println("Exit Code: "+process.exitValue());
//System.out.printf("Output of running %s is:", Arrays.toString(args));
/* while ((line = br.readLine()) != null) {
System.out.println(line);
}*/
}
}
But this program is giving me an error :
Exception in thread "main" java.lang.IllegalThreadStateException: process hasn't exited
at java.lang.UNIXProcess.exitValue(UNIXProcess.java:172)
at ExecBashCommand.main(ExecBashCommand.java:16)
Any suggestions as to how to get the exit value. Thanks
