I am a src committer.
I often start with the lowest release that I intend to back port to (e.g., RELENG_11_3.
I would then do (before or after making changes):
make buildworld
then deploy to a jail directory:
make DESTDIR=/usr/jails/test installworld
This jail directory, as the first responder hinted, can be used with bhyve, but I find it easier to configure a jail or even just use chroot.
I like to configure my jails in /etc/rc.conf instead of /etc/jail.conf:
Example /etc/rc.conf contents:
jail_enable="YES"
jail_list="test"
jail_test_rootdir="/usr/jails/test"
jail_test_hostname="test"
jail_test_devfs_enable="YES"
I can provide more in-depth examples, ones where the jail has a private networking stack so you can SSH into it, for example, but I don't get the sense that a networking stack is important to your testing from the posted question.
You can see the running jail with "jls" and you can enter the running jail with "jexec test bash"
Inside the jail you can test your changes.
When doing this kind of sandboxing, jails work so long as the /usr/src that you built/installed to the jail is from a release that is:
- Older than the guest OS, or
- In the same STABLE branch as the guest OS, or
- At the very least binary-compatible with the guest OS
Situations 1 and 2 are pretty safe, while situation 3 (e.g., running a newer /usr/src than the guest OS) can get dodgy. For example, trying to run /usr/src head (13.0-CURRENT) on a 12.0-RELEASE-pX guest OS where the KBI, KPI, and API can all differ between kernel and userland (with jails, each jail runs under the guest OS's kernel).
If you find that you have to run the newest sources against an older guest OS, then bhyve is definitely the solution. You would take that jail directory and instead of running a jail with that root directory, run a bhyve instance with the jail directory as its root. I don't use bhyve that often, so I can't recall if you first have to deposit the contents inside a disk image and point bhyve at the disk image first -- others and/or Google would know the answer to that.