Out of the 4 tables that I have, 3 contain similar(client,policyno,policytype..) fields but with different data. The other table, however, has very different fields(client,sex,telephone,dob..). I have a search box in my view that makes use of the telephone number to display related records from all the 3 tables. Unfortunately, I am not able to handle the fields of the fourth table. Keeps returning the error
System.IndexOutOfRangeException: 'PolicyNo'
My Model:
public class TableModels
{
[Key]
[DatabaseGenerated(DatabaseGeneratedOption.Identity)]
public int ID { get; set; }
public string Client { get; set; }
public string PolicyNo { get; set; }
public short? PolicyType { get; set; }
public string Telephone { get; set; }
//Health
public DateTime? DOB { get; set; }
public string Sex { get; set; }
public string DepMemberNumber { get; set; }
protected TableModels ReadValue(SqlDataReader reader)
{
TableModels obj = new TableModels();
if (reader["ID"] != DBNull.Value)
{
obj.ID = (int)reader["ID"];
}
if (reader["Client"] != DBNull.Value)
{
obj.Client = (string)reader["Client"];
}
if (reader["PolicyNo"] != DBNull.Value)
{
obj.PolicyNo = (string)reader["PolicyNo"];
}
if (reader["PolicyType"] != DBNull.Value)
{
obj.PolicyType = (short)reader["PolicyType"];
}
The error is returned on the Protected TableModel class.
Any advice would be appreciated
View:
@model IEnumerable
@foreach (var item in Model.OrderByDescending(m => m.Client))
{
<tr>
<td>
@Html.DisplayFor(modelitem => item.Client)
</td>
<td>
@Html.DisplayFor(modelitem => item.Telephone)
</td>
<td>
@Html.ActionLink("Details", "Details", new { id = item.Telephone })
</td>
</tr>
}
Controller:
public ActionResult Details(string id)
{
using (MainContext db = new MainContext())
{
if (id == null)
{
return new HttpStatusCodeResult(System.Net.HttpStatusCode.BadRequest);
}
List<SingleView> x1 = db.SingleViews.Where(a => a.Telephone == id).ToList();
List<SingleViewM> x2 = db.SingleViewMs.Where(a => a.Telephone == id).ToList();
List<SingleViewWst> x3 = db.SingleViewWsts.Where(a => a.Telephone == id).ToList();
List<PensionsView> x4 = db.PensionsViews.Where(a => a.Telephone == id).ToList();
List<Health> x5 = db.Health.Where(a => a.Telephone == id).ToList();
SingleModel objview = new SingleModel();
objview.USSD = x1;
objview.Mombasa = x2;