Regex_replace from boost library doesn't work as expected

Question

I am trying remove a substring following a pattern.

I am trying to use the boost library as it provides the regex_replace, which as I understood should replace every occurence of the regex with my given new string.

std::string s("m_value[0..3]");
boost::regex rgx("\[.*\]");
return boost::regex_replace(s, rgx, "");

This code returns m_value[03] instead of m_value. Any ideas why?

[Compile with warnings on](https://gcc.godbolt.org/z/aEDjU1) — chris, Nov 06 '19 at 12:34

score 2 · Accepted Answer · answered Nov 06 '19 at 12:34

2

You forget to escape the escape.

You need two backslashes to add a backslash in strings:

boost::regex rgx("\\[.*\\]");

Or use raw string literals:

boost::regex rgx(R"(\[.*\])");

answered Nov 06 '19 at 12:34

Some programmer dude

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Of course. It got a little confusing writing regex in a string. Thank you. – Tituuss10 Nov 06 '19 at 12:37

Regex_replace from boost library doesn't work as expected

1 Answers1