label getting duplicated every time a new bar is presented

Question

i write pine with Tradingview and each time there is a new bar my text is being duplicated. i need the label to move to the new bar only.

//@version=4
study("My Script")

plot(close)

label.new (barstate.islast ? time : na,close,text="test",xloc=xloc.bar_time)

PineCoders-LucF · Answer 1 · 2019-11-05T19:27:24.747

6

This code first deletes the last label created and then creates a new one, which will in turn be deleted on the next bar, so you're always left with only one label:

//@version=4
study("")
var label lbl = na
label.delete(lbl)
// Original line.
// lbl := label.new (barstate.islast ? time : na,close,text="test",xloc=xloc.bar_time)
// Place label 4 bars back.
lbl := label.new (barstate.islast ? bar_index - 4 : na,close,text="test",xloc=xloc.bar_index)

edited Nov 05 '19 at 19:27

answered Nov 05 '19 at 02:25

PineCoders-LucF

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Another question you might help me, how do i get the last candle index number ? – Oren Teich Nov 05 '19 at 09:46
You can use `last = not barstate.isconfirmed ? bar_index : na`. The index starts at 0 on the dataset's first bar, so actual number of bars in dataset is that value + 1. – PineCoders-LucF Nov 05 '19 at 14:57
THANKS :-) im trying to display label 5 bars back from the active bar. i tried: last = not barstate.isconfirmed ? bar_index : na label.new (bar_index==last-5 ? bar_index:na,0,text="X",xloc = xloc.bar_index) – Oren Teich Nov 05 '19 at 18:44
Very cool !another question, how do turn a specific value in series to be single variable ? – Oren Teich Nov 06 '19 at 19:35
You can't. Impossible to achieve the equivalent of passing an argument as a value instead of a pointer, let's say, except when "de-serializing" a series value by using it as a base with constant `[x]` index in a `for` loop and indexing other series values using the `for` loop's counter. – PineCoders-LucF Nov 06 '19 at 22:57

Clark Baker · Answer 2 · 2023-02-10T03:42:09.203

0

If anyone comes across this trying to draw a line or something else on only the last bar, like me, and getting frustrated with barstate.islast, here you go...

if bar_index == last_bar_index
    line.new(bar_index, y1, bar_index+1, y2)
    if array.size(line.all) > 1
        line.delete(array.get(line.all, array.size(line.all)-1))

edited Feb 10 '23 at 03:42

answered Feb 10 '23 at 02:59

Clark Baker

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score 0 · Answer 3 · edited Apr 04 '23 at 16:41

0

It turns out this works:

indicator("test",overlay=true,max_labels_count=1)

edited Apr 04 '23 at 16:41

Tyler2P

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answered Apr 04 '23 at 01:51

Matthew Whitmore

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Your answer could be improved by providing an example of the solution and how it helps the OP. – Tyler2P Apr 04 '23 at 16:41

score -2 · Answer 4 · answered Dec 03 '19 at 21:28

-2

solved like hell :-) Asking for help, clarification, or responding to other answers.

answered Dec 03 '19 at 21:28

Oren Teich

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label getting duplicated every time a new bar is presented

4 Answers4