Beginner - Splitting lists

Question

I currently have one list with x amount of items (number of items may change each time I use the program).

Example:

['This is in index 0, This is in index 0, This is in index 0, This is in index 0' , 
'This is in index 1, This is in index 1, This is in index 1']

I would like to be able to split each index into different lists and have each index of the newly created lists separated by the comma to produce something like below.

['This was in index 0,' 'This was in index 0,' 'This was in index 0,' 'This was in index 0'] 
['This was in index 1,' 'This was in index 1,' 'This was in index 1']

This is the my first ever attempt at writing anything useful so any help and explanations would be hugely appreciated.

What have you tried? What specifically do you need help with? — Carcigenicate, Nov 04 '19 at 14:17
Some hint : you need to iterate over your list to get each string then you can use `list comprehension`. You may use str.split() [Check this documentation](https://www.geeksforgeeks.org/python-string-split/) — Clément, Nov 04 '19 at 14:25
Thanks for all the responses, I have found an answer elsewhere on here. Thanks again — Dean1886, Nov 04 '19 at 14:35

score 2 · Answer 1 · answered Nov 04 '19 at 14:23

You can do this:

input_list = ["this is index 0, this is index 0, this is index 0", "this is index 1, this is index 1, this is index 1"]
output_list = []

for i in input_list:
    split_string = i.split(",")
    output_list.append(split_string)

print(output_list)

EDIT: This is iterating over the original list, splitting each index by a comma, then adding the resultant list to the 'output_list', which is a list containing two lists, each nested list is the split 'this is index X' list.

c4llmeco4ch · Answer 2 · 2019-11-04T14:36:13.183

One of the simpler ways would be the use of the sublist syntax

name_of_list[start:end:step]

As such, if we pretend you know there are 4 0's and 3 1's, you could try:

ohs = 4
ones = 3
only0s = my_list[:ohs] #when you neglect the first value, it's assumed 0
only1s = my_list[ohs:] #when you leave out the last value, it's assumed len(list)

Alternatively, you can use negatives to represent from the end, so...

backOhs = my_list[:-ones]
backOnes =my_list[-ones:]

EDIT: as an aside, this also works with lists, so...

my_word = 'hello'
print(my_word[2:4])

Prints 'll'

score 0 · Answer 3 · answered Nov 04 '19 at 14:25

You can use list comprehension to separate the data like this:

original = ['This is in index 0, This is in index 0, This is in index 0, This is in index 0' ,'This is in index 1, This is in index 1, This is in index 1']

list_zero = [x for x in original if '0' in x]

The result would be :

['This is in index 0, This is in index 0, This is in index 0, This is in index 0']

Then repeat for list one:

list_one = [x for x in original if '1' in x]

Here is a website you can use to learn more about list comprehensions.

score 0 · Answer 4 · answered Nov 04 '19 at 14:27

you can use this code:

main_list= ['This is in index 0, This is in index 0, This is in index 0, This is in 
index 0' , 'This is in index 1, This is in index 1, This is in index 1']
matrix=[]
for item in main_list:
    sub_list=item.split(",")
    matrix.append(sub_list)

and for output you can call this :

print(matrix[0])
print(matrix[1])
>>>['This is in index 0', ' This is in index 0', ' This is in index 0', ' This is in index 0']
>>>['This is in index 1', ' This is in index 1', ' This is in index 1']

Beginner - Splitting lists

4 Answers4