Max value of list of list in Python

Question

I'm looking for the max of item[6] in a list of list. Also I need the index of the list. 13 vs 23 = 23 and comparation[1] in this case. Any way to do that?

comparation = [
    [(Timestamp('2018-02-08 00:00:00'), 26, 211.8711395263672), (Timestamp('2018-02-21 00:00:00'), 34, 222.0032501220703), 1.2665138244628906, 178.94178009033203, 'MIN', (39, Timestamp('2018-02-28 00:00:00')), 13, 398],
    [(Timestamp('2018-02-08 00:00:00'), 26, 211.8711395263672), (Timestamp('2018-03-02 00:00:00'), 41, 220.2726287841797), 0.5600992838541666, 197.30855814615884, 'MIN', (49, Timestamp('2018-03-14 00:00:00')), 23, 388]
]

b = [max(p) for p in comparation]

BTW, it's spelled `comparison`. – Karl Knechtel Oct 31 '19 at 01:14 — Karl Knechtel, Oct 31 '19 at 01:14

score 3 · Accepted Answer · answered Oct 31 '19 at 00:41

3

max function has a key argument you can use for this purpose:

max(comparation, key=lambda x: x[6])

answered Oct 31 '19 at 00:41

Selcuk

57,004
12
102
110

Max value of list of list in Python

1 Answers1