sort with two element in list of tuple in python3

Question

[('sara', 75, 180), ('marko', 90, 190), ('jaimi', 75, 175), ('alex', 60, 175)]

I want to sort this list based on height and weight. The second element of each tuple is weight and the third is height.

Task: First sort by height (tall to short). If some element's height is equal sort that element with weight (slim to fat).

The output should be like this:

[('marko', 90, 190), ('sara', 75, 180), ('alex', 60, 175), ('jaimi', 75, 175)]

I still doing this code:

x=sorted(result,key=lambda x: (x[2],x[1]),reverse=True)

Welcome to Stack Overflow! Check out the [tour]. It's helpful to mention specific problems, like in this case, it looks like your code not sorting properly. — wjandrea, Oct 29 '19 at 14:18

yatu · Answer 1 · 2019-10-29T14:10:18.443

3

Instead of specifying reverse=True, you can change the sign of the height to have the ordering both in descending and ascending order respectively:

sorted(result, key=lambda x: (-x[2], x[1]))
# [('marko', 90, 190), ('sara', 75, 180), ('alex', 60, 175), ('jaimi', 75, 175)]

edited Oct 29 '19 at 14:10

answered Oct 29 '19 at 14:04

yatu

Keeping `reverse` if fine with changing the sign of `x[1]`: `sorted(l, key=lambda x: (x[2], -x[1]), reverse=True)` – heemayl Oct 29 '19 at 14:08
Yes it's the same but less code @heemayl – yatu Oct 29 '19 at 14:09

1 Answers1