Let's first construct a CSV file.
str = <<~END
name,contacts.0.phone_no,contacts.1.phone_no,codes.0,IQ,codes.1
YK,1234,4567,AB001,173,AK002
ER,4321,7654,BA001,81,KA002
END
FName = 't.csv'
File.write(FName, str)
#=> 121
I have constructed a helper method to construct a pattern that will be used to convert each row of the CSV file (following the first, containing the headers) to an element (hash) of the desired array.
require 'csv'
def construct_pattern(csv)
csv.headers.group_by { |col| col[/[^.]+/] }.
transform_values do |arr|
case arr.first.count('.')
when 0
arr.first
when 1
arr
else
key = arr.first[/(?<=\d\.).*/]
arr.map { |v| { key=>v } }
end
end
end
In the code below, for the example being considered:
construct_pattern(csv)
#=> {"name"=>"name",
# "contacts"=>[{"phone_no"=>"contacts.0.phone_no"},
# {"phone_no"=>"contacts.1.phone_no"}],
# "codes"=>["codes.0", "codes.1"],
# "IQ"=>"IQ"}
By tacking if pattern.empty?
onto the above expression we ensure the pattern is constructed only once.
We may now construct the desired array.
pattern = {}
CSV.foreach(FName, headers: true).map do |csv|
pattern = construct_pattern(csv) if pattern.empty?
pattern.each_with_object({}) do |(k,v),h|
h[k] =
case v
when Array
case v.first
when Hash
v.map { |g| g.transform_values { |s| csv[s] } }
else
v.map { |s| csv[s] }
end
else
csv[v]
end
end
end
#=> [{"name"=>"YK",
# "contacts"=>[{"phone_no"=>"1234"}, {"phone_no"=>"4567"}],
# "codes"=>["AB001", "AK002"],
# "IQ"=>"173"},
# {"name"=>"ER",
# "contacts"=>[{"phone_no"=>"4321"}, {"phone_no"=>"7654"}],
# "codes"=>["BA001", "KA002"],
# "IQ"=>"81"}]
The CSV methods I've used are documented in CSV. See also Enumerable#group_by and Hash#transform_values.