A simple way is pass 'State' of your Stateful Widget as a parameter to your 'Model'.
Like this:
class Model extends ChangeNotifier {
Model(this.yourState);
YourState yourState;
bool get _isMounted => yourState.mounted;
}
class YourState extends State<YourStatefulWidget> {
Model model;
@override
void initState() {
super.initState();
model = Model(this);
}
@override
Widget build(BuildContext context) {
// your code..
}
}
I think you don't need to check the State
is mounted or not. You just need to check the Model has been already disposed. You can override dispose()
method in ChangeNotifier
:
class Model extends ChangeNotifier {
bool _isDisposed = false;
void run() async {
await Future.delayed(Duration(seconds: 10));
if (!_isDisposed) {
notifyListeners();
}
}
@override
void dispose() {
super.dispose();
_isDisposed = true;
}
}
And don't forget dispose Model
when the State
is disposed:
class YourState extends State {
Model model;
@override
void initState() {
super.initState();
model = Model();
}
@override
void dispose() {
model?.dispose();
super.dispose();
}
/// Your build code...
}
Or you can use ChangeNotifierProvider
in package Provider, it will help you to dispose Model
automatically.
class YourState extends State {
Model model;
@override
void initState() {
super.initState();
model = Model();
}
@override
Widget build(BuildContext context) {
return ChangeNotifierProvider<Model>(
builder: (build) => model,
child: Container(
child: Consumer<Model>(
builder: (context, model, widget) => Text("$model"),
),
),
);
}
}