Is there a more concise way of getting today's date, at a specified time in python

Question

I need a datetime object whose date is today's date, but whose time is specified (3 am).

I tried this:

dt.now().date() + timedelta(hours=3)

-> Can't add timedelta to dt.date object

foo = dt.now()
foo.hour = 3
foo.minute = 0
foo.second = 0

-> Not writable

This works, but seems ugly:

foo = dt(dt.now().year, dt.now().month, dt.now().day, 3,0,0,0)

Or, alternatively:

foo = dt(dt.now().year, dt.now().month, dt.now().day) + timedelta(hours=3)

Is there a cleaner, more pythonic way of doing this? It feels like 'today at a specific time' should be a fairly common use case...

`In[1]: dt.datetime.now().date() + datetime.timedelta(hours=3)`, `Out[1]: datetime.date(2019, 10, 25)`. no problems with python 3.6.5 — JHBonarius, Oct 25 '19 at 10:56
@JHBonarius. The problem is that your result is a date that discarded the time information — Mad Physicist, Oct 25 '19 at 11:01
@MadPhysicist true. but no "Can't add timedelta to dt.date object" — JHBonarius, Oct 25 '19 at 11:02

score 2 · Accepted Answer · answered Oct 25 '19 at 11:00

Just like datetime.datetime has a classmethod now, datetime.date has a method today (which is different form datetime.datetime.today).

You can use this method along with datetime.datetime.combine for a reasonably clean solution:

_3am = time(3, 0, 0)
dt = datetime.combine(date.today(), _3am)

score 1 · Answer 2 · answered Oct 25 '19 at 10:55

1

Try the below:

foo = dt.datetime.combine(dt.date.today(), dt.time(3))

answered Oct 25 '19 at 10:55

Sam

2 Answers2