How to unzip 7z to get all files in the powersehll

Question

I am working on a power shell script. I have a 7z file which has 2 files inside it. I want to unzip this 7z file in the same directory where the 7z file is and get the full names of the 2 files inside the 7z. I have to do all this using power shell.

Currently my script is:

set-alias sz "$env:ProgramFiles\7-Zip\7z.exe"
sz x -o$unZipFoldersPath $compressedfolder.FullName -r

I am getting the error

Cannot find archive

Is not the argument after -o is the output where we have to store our unzip file ?

take a look here: https://stackoverflow.com/questions/42998669/unzip-file-using-7z-in-powershell — Patrick, Oct 15 '19 at 09:22
I was following this, but i am unable to get the extracted file in the output directory @Patrick — Waleed Naveed, Oct 15 '19 at 09:23

score 0 · Answer 1 · answered Oct 15 '19 at 10:45

0

That one seems to work:

set-alias sz "$env:ProgramFiles\7-Zip\7z.exe"    
$Destination = 'C:\Temp\Destination'
$Source =  = 'C:\Temp\Source' #*.7z files inside

#-r parameter looks for all *.7z files
sz x -o"$($unZipFoldersPath)" "$($Source)" -r

answered Oct 15 '19 at 10:45

Patrick

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How to unzip 7z to get all files in the powersehll

1 Answers1