How to remove %20 from url in python?

Question

How do I remove %20 from url in my code?

elif 'launch' and 'open' in voice_note:
    print('opening...')
    start_url = "https://www."
    end_url = ".com"
    urllib.parse.unquote(voice_note)
    play_sound_from_polly('Displaying the result, sir')
    webbrowser.open(start_url + voice_note.replace('open', '').replace('%20', '') + end_url)
    exit()

Here is a image of what it opens image

Check the contents of `voice_note` and see if that's what you expect or not. — , Oct 14 '19 at 14:45
It's not `%20`. It's a space. Do `.strip()` after removing `'open'` or change second `replace` to remove spaces. — h4z3, Oct 14 '19 at 14:45
%20 is a space so you can remove space in voice_note by doing voice_note .strip() — jose_bacoy, Oct 14 '19 at 14:45

score 2 · Answer 1 · answered Oct 14 '19 at 14:45

2

%20 is the url encoding for the space : ' ' character, so you want to strip or replace the ' ' in your url string.

answered Oct 14 '19 at 14:45

Maxime

818
6
24

score 0 · Accepted Answer · answered Oct 14 '19 at 14:59

Instead of doing this:

webbrowser.open(start_url + voice_note.replace('open', '').replace('%20', '') + end_url)

Use strip() function:

webbrowser.open(start_url + voice_note.replace('open', '').strip() + end_url)

Or simply put:

webbrowser.open(start_url + voice_note.replace('open', '').replace(' ', '') + end_url)

The reason is you are trying to replace '%20' and not a space. %20 is an encoded value of space in a url.

How to remove %20 from url in python?

2 Answers2