printf() is printing the wrong value

Question

This is my full code, and its printing random negative values each time I run it not sure what is wrong. using Ubuntu to run and "gcc -Wall -Wextra test.c"

#include <stdio.h>
int main () {

unsigned int x = 10;
unsigned int y = 16;
unsigned int p = x + y;

printf("%d\n", &p);

return 0;
}

Why did you write `&p`? Were you thinking of `scanf`? In this case, you're passing `p`'s value to `printf`, so you don't want the `&`. — Steve Summit, Oct 13 '19 at 20:51

Jonathan Wood · Accepted Answer · 2019-10-15T16:12:11.707

8

You are passing the address of p. You need to pass the value.

printf("%d\n", p);

As you have it, your code is printing the address of p, whatever that happens to be.

In addition, since you are using unsigned int, you probably want to use the %u formatter insted of %d.

edited Oct 15 '19 at 16:12

answered Oct 13 '19 at 20:23

Jonathan Wood

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printf() is printing the wrong value

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