list() function returns null php

Question

I've tried to refactor my code by using the list() php function but it returns null and I am not sure what I am not doing well. My code:

 public function test() {
      // content
      return ['variable' => $variable, 'variable1' => $variable1];
 }


 //
 list($variable, $variable1) = test();

I thought that's the way to use list(). Can someone give me a hint on what I am not doing alright?

no, the $variable is set in the `//content'. When I debug and I am at the return, the $variable and $variable1 are set. $variable is an array, and the other one is a string. — IleNea, Oct 13 '19 at 13:18
Think https://stackoverflow.com/a/41253379/1213708 is the best answer from the duplicate (if your using PHP 7.1+) — Nigel Ren, Oct 13 '19 at 13:38

score 1 · Answer 1 · answered Oct 13 '19 at 13:20

function list() is working for the numeric array only, in your case you should use extract() function

 function test() {
  return ['variable' => 11, 'variable1' => 12];
 }
 extract(test());
 echo $variable.'--'.$variable1;

Working example : https://3v4l.org/aVkpI

list() function returns null php

1 Answers1