How to access the human-readable name using get_FOO_display

Question

Hello I have the next code to show to my participants the text of the response that the gave me in a anterior session.

    J11 = models.IntegerField(
        choices=[
            [-2, 'Muy moralmente inapropiado'],
            [-1, 'Moralmente inapropiado'],
            [0, 'No aplica'],
            [1, 'Moralmente apropiado'],
            [2, 'Muy moralmente apropiado'],
        ],
        widget=widgets.RadioSelect
    )
    TJ11 = models.CharField(max_length=2, choices=J11)

When I try to prove this code I get the next error:

File "C:\Users\diese\iat\incentivos\models.py", line 140, in <module>
 class Player(BasePlayer):
File "C:\Users\diese\iat\incentivos\models.py", line 216, in Player
 TJ11 = models.CharField(max_length=2, choices=J11)
File "c:\users\diese\appdata\local\programs\python\python37\lib\site-packages\otree\db\models.py",   line 386, in __init__super().__init__(max_length=max_length, **kwargs)
File "c:\users\diese\appdata\local\programs\python\python37\lib\site-packages\otree\db\models.py", line 217, in __init__
fix_choices_arg(kwargs)
File "c:\users\diese\appdata\local\programs\python\python37\lib\site-packages\otree\db\models.py",   line 195, in fix_choices_arg
choices = expand_choice_tuples(choices)
File "c:\users\diese\appdata\local\programs\python\python37\lib\site- packages\otree\common_internal.py", line 118, in expand_choice_tuples
if not isinstance(choices[0], (list, tuple)):
TypeError: 'IntegerField' object is not subscriptable

What Can I do? Someone has experienced the same ?

Thanks in advance

The error is coming from the field `TJ11` that has not been shared in your question — Iain Shelvington, Oct 10 '19 at 23:09
`choices=J12` - `J12` is a field and not an iterable of choices. Do you want 2 fields with the same choices? — Iain Shelvington, Oct 10 '19 at 23:13
Yes, there is Likert scale so I need a lot of fields with the same choices — Sebastián Ramírez, Oct 10 '19 at 23:15

Iain Shelvington · Accepted Answer · 2019-10-10T23:29:35.370

0

You can define choices before you define your field and then assign those choices to the field afterwards . This allows you to assign those choices to multiple fields:

MY_CHOICES = (
    (-2, 'Muy moralmente inapropiado'),
    (-1, 'Moralmente inapropiado'),
    (0, 'No aplica'),
    (1, 'Moralmente apropiado'),
    (2, 'Muy moralmente apropiado'),
)
J11 = models.IntegerField(choices=MY_CHOICES)
TJ12 = models.CharField(max_length=20, choices=MY_CHOICES)

edited Oct 10 '19 at 23:29

answered Oct 10 '19 at 23:18

Iain Shelvington

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In that way I shouldn't get this error 'IntegerField' object is not subscriptable? I am trying to call the text in the choice to other template of my app – Sebastián Ramírez Oct 10 '19 at 23:23
No, because you wouldn't be passing an IntegerField as the value for choices to another field – Iain Shelvington Oct 10 '19 at 23:25
One last question how should I call this value in my template? In the next form: player.get_J12_display() ? – Sebastián Ramírez Oct 10 '19 at 23:27
Yeah that's a fine way of getting the selected value of the field – Iain Shelvington Oct 10 '19 at 23:28
I get the next error : File "C:\Users\diese\iat\incentivos\models.py", line 220 J11 = models.IntegerField(choices=MY_CHOICES) ^ SyntaxError: invalid syntax – Sebastián Ramírez Oct 10 '19 at 23:33
There isn't any syntax error in that code, can you share the entire model code in your question? – Iain Shelvington Oct 10 '19 at 23:35
The code is very long, more or less 1000 lines, should i post it ? – Sebastián Ramírez Oct 10 '19 at 23:38
Maybe, try copying the code again, maybe you missed something? – Iain Shelvington Oct 10 '19 at 23:40
Okey, I changed it, and this see the same. – Sebastián Ramírez Oct 10 '19 at 23:44

How to access the human-readable name using get_FOO_display

1 Answers1