Stored that time format in some other file. And retrieve this as string. How to change this to time format again.
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You can use strptime to parse the time, and then mktime to convert it to a time_t
const char *time_details = "Thu Oct 3 18:45:10 2019";
struct tm tm;
// %a or %A
// The weekday name according to the current locale, in abbreviated form or the full name.
// %b or %B or %h
// The month name according to the current locale, in abbreviated form or the full name.
// the field descriptors must match the string format you are providing.
strptime(time_details, "%a %b %d %H:%M:%S %Y", &tm);
time_t t = mktime(&tm);
You can find the detailed usage of input field descriptors at strptime(3)
Bhawan
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I tried that. But won't work – user10769166 Oct 04 '19 at 06:10
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What is meant by 'wont work'? Any error or output? Please share – Bhawan Oct 04 '19 at 06:13
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my code : struct tm tim ; char *current_time; time_t tm = time(NULL); current_time = strtok(ctime(&tm), "\n"); cout << "before" << tm <
– user10769166 Oct 04 '19 at 06:58 -
output gets varied for the same input – user10769166 Oct 04 '19 at 07:01
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time(NULL) is returning current time. Your current time is changing. So, output will change too. – Bhawan Oct 04 '19 at 07:24