I try to find the best way to check if a CHAR/VARCHAR2
variable contains characters (NULL
or spaces should be considered the same, as "no-value"):
I know there are several solutions, but it appears that (NVL(LENGTH(TRIM(v)),0) > 0)
is faster than (v IS NOT NULL AND v != ' ')
Any idea why? Or did I do something wrong in my test code?
Tested with Oracle 18c
on Linux, UTF-8 db charset
...
I get the following results:
time:+000000000 00:00:03.582731000
time:+000000000 00:00:02.494980000
set serveroutput on;
create or replace procedure test1
is
ts timestamp(3);
x integer;
y integer;
v char(500);
--v varchar2(500);
begin
ts := systimestamp;
--v := null;
v := 'aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa';
for x in 1..50000000
loop
if v is not null and v != ' ' then
y := x;
end if;
end loop;
dbms_output.put_line('time:' || (systimestamp - ts) ) ;
end;
/
create or replace procedure test2
is
ts timestamp(3);
x integer;
y integer;
v char(500);
--v varchar2(500);
begin
ts := systimestamp;
--v := null;
v := 'aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa';
for x in 1..50000000
loop
if nvl(length(trim(v)),0) > 0 then
y := x;
end if;
end loop;
dbms_output.put_line('time:' || (systimestamp - ts) ) ;
end;
/
begin
test1();
test2();
end;
/
drop procedure test1;
drop procedure test2;
quit;