Why does the following function return undefined?

Asked Sep 26 '19 at 06:17

Active Sep 26 '19 at 06:19

Viewed 40 times

function iqTest(numbers) {
  const split = numbers.split(" ");

  split.forEach((l, index) => {
    if (l % 2 === 0) {
      return index + 1;
    }
  })
}

This is from a CodeWars question. I reckon it looks like the return is missed in the anon function.. but why is that so?

edited Sep 26 '19 at 06:18

ellipsis

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asked Sep 26 '19 at 06:17

Mike K

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`return` inside the `forEach` callback terminates the `forEach` callback function, nothing else. You're probably looking for `findIndex` instead – CertainPerformance Sep 26 '19 at 06:19
Makes sense, thanks! – Mike K Sep 26 '19 at 06:25

Why does the following function return undefined?

0 Answers0