How to simulate ReLU gradient with tf.GradientTape

Question

TensorFlow has a feature called GradientTape, kinda getting gradients using Monte Carlo method(?).

I'm trying to simulate the gradient of ReLU but this doesn't work on the negative half of X.

#colab or ipython reset
%reset -f

#libs
import tensorflow as tf;

#init
tf.enable_eager_execution();

#code
x = tf.convert_to_tensor([-3,-2,-1,0,1,2,3],dtype=tf.float32);

with tf.GradientTape() as t:
  t.watch(x);
  y = fx = x; #THIS IS JUST THE POSITIVE HALF OF X

dy_dx = t.gradient(y,x);
print(dy_dx);

Guess I have to change something at the line y = fx = x, like adding a if x<=0 but can't figure out how.

The above code prints out:

tf.Tensor([1. 1. 1. 1. 1. 1. 1.], shape=(7,), dtype=float32)

But it is wanted to be:

tf.Tensor([0. 0. 0. 0. 1. 1. 1.], shape=(7,), dtype=float32)

score 0 · Accepted Answer · answered Sep 26 '19 at 06:42

The following grad function simulate the conditional X of ReLU function but I don't know whether it's the proposed, suggested way to do it:

#ipython
%reset -f

#libs
import tensorflow as tf;
import numpy      as np;

#init
tf.enable_eager_execution();

#code
X = tf.convert_to_tensor([-3,-2,-1,0,1,2,3], dtype=tf.float32);

with tf.GradientTape() as T:
  T.watch(X);
  Y = Fx = X;
#end with

Dy_Dx = T.gradient(Y,X);
#print(Dy_Dx);

#get gradient of function Fx with conditional X
def grad(Y,At):
  if (At<=0): return 0;

  for I in range(len(X)):
    if X[I].numpy()==At:
      return Dy_Dx[I].numpy();
#end def

print(grad(Y,-3));
print(grad(Y,-2));
print(grad(Y,-1));
print(grad(Y,-0));
print(grad(Y,1));
print(grad(Y,2));
print(grad(Y,3));

print("\nDone.");
#eof

How to simulate ReLU gradient with tf.GradientTape

1 Answers1