Is there assign a dunder method a custom operator?

Asked Sep 25 '19 at 00:26

Active Apr 30 '20 at 21:28

Viewed 349 times

So I was wondering is it possible to make a new dunder method that has its own operator? Something like this:

class test:
  def __init__(self, name):
     self.name = name
     pass
  def __user__(self, times):
    return(self.name*times)

---------- 
Run
----------

Python 3.7.1 Shell

>>> a = test('stackoverflow')
>>> a -!? 1
'stackoverflow'
>>>

Thanks in Advance!

**EDIT: ** Thank you @user2357112-supports-Monica and @Mad-Physicist for explaining to me what I wanted to do is impossible (without recompiling Python that is...) and how to do my original example.

edited Apr 30 '20 at 21:28

asked Sep 25 '19 at 00:26

RhinoCodes

2

There's already a method for `@`. It's `__matmul__`, because `@` is intended for matrix multiplication. – user2357112 Sep 25 '19 at 00:27
You can't add your own operator, but you can implement the defined ones as you choose. What's your specific question? – Mad Physicist Sep 25 '19 at 00:29
what are you trying to accomplish with a custom dunder method? – Mason Caiby Sep 25 '19 at 00:36
Well it was to make a custom operator but now I know I cant do that – RhinoCodes Sep 25 '19 at 00:36

Is there assign a dunder method a custom operator?

0 Answers0