Ordering file content in alphabetic order using Python

Question

In Python, I'm getting a list with emptiness ( i.e. [ ] ) in it and testing mechanics indicate that its not sorting the content properly. It fails to pass the sorting of items contained in a file.

Write a program that inputs a text file. The program should print the unique words in the file in alphabetical order.

textFile = input("Input a file name: ")

with open(textFile) as objects:

textReader = objects.readlines()
textReader.sort()
print(textReader)

Output: [ ]

Try to identify your problem clearly. – AbdelAziz AbdelLatef Sep 22 '19 at 03:17 — AbdelAziz AbdelLatef, Sep 22 '19 at 03:17

score 0 · Answer 1 · answered Sep 21 '19 at 23:43

You didn't specify the language this needs to be in. If you would use Ruby it's like this.

File.read('input.txt').split(/\W/).uniq.sort

The only thing I believe that needs an explanation is the split(/\W/) thing. It's an regular expression (google is your best friend) which means split the text by any non textual characters like spaces and put them in an array.

Ordering file content in alphabetic order using Python

1 Answers1