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When we request to google or any 3rd party API, in this return url we getting this type of code.

?code=4/rAERtRkfXf--

The server doesn't accept this type code and it's showing 403 forbidden Error.

When I am talking with server support they told me about the security issue and it's mod_security issue.

Can anybody help me to solve this type of issue?

Rockers Technology
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  • You need to speak to your hosting provider who can advise what ModSecurity rule that is catching this and how to add an exception to that rule for the `code` argument. – Barry Pollard Sep 18 '19 at 18:02

1 Answers1

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Try doing str_replace('/','%2F',$your_url) before submitting it to the server

Antony
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