Print a list of heights with "#" symbol

Question

today I bring you an apparently simple question, that it's not so simple as it seems(for me at least)!

Imagine I have the following list of integers:

num = [3,1,1,2]

And I want to print "$" corresponding with the height i.e:


&
&     & 
& & & &


for i in num:
    print("#"*i)

prints this:

& & &
&
&
& &

However I want the former displayed!

I tried this:


for i in range(1, max(num)+1): # loops through the rows 
   for j in num:
       if j == i:
            print("#")
       else:
            print("")

But after a while I understood that the condition doesn't make any sense, because I'm comparing row numbers with the height!

I tried other stuff but none of them worked properly, I would appreciate if someone could help me out! Thanks

you can store them in a matrix and then transpose it and print. — vb_rises, Sep 10 '19 at 15:48
And how would you store this values in the matrix ? (without numpy) — José Rodrigues, Sep 10 '19 at 15:52
ok, can you show the expected output for the input `[1, 3, 1, 1, 2, 5]` ? — RomanPerekhrest, Sep 10 '19 at 15:53
@RomanPerekhrest, each number on the list correspond to the number of vertical symbols, so you'd have 1 symbol , 3 symbols , 1 symbol ... m 5 symbols all displayed horizontally — José Rodrigues, Sep 10 '19 at 15:56
Are you using `$`, `&`, or `#` your question is insconsistent the entire way. — Error - Syntactical Remorse, Sep 10 '19 at 17:07

Chris · Accepted Answer · 2019-09-10T16:05:02.987

5

I would just iterate backwards from the max number, checking each element in your list if it is greater to or equal to that number, and printing the desired character, else printing a space.

>>> for x in range(max(num), 0, -1):
...     print(''.join(['&' if i >= x else ' ' for i in num]))
...
&
&  &
&&&&

edited Sep 10 '19 at 16:05

answered Sep 10 '19 at 15:56

Chris

15,819
3
24
37

There should be a space between horizontal &'s – Sep 10 '19 at 15:58
it should be `' '.join(...` you can delete space inside `& ` to make it more readable. – Sep 10 '19 at 16:00
@joumaico happy now? :P – Chris Sep 10 '19 at 16:01
@joumaico it just messes w/the spacing in the print statement so it lines up wrong if i do that. – Chris Sep 10 '19 at 16:06
It's not displaying correctly row number 2, should have $ in the first columns and last column, you have the symbol in the 3rd column, it should be on the 4th (last)! – José Rodrigues Sep 10 '19 at 16:08
@Chris Thank you so much this was very helpful! I have a suggestion! If you add a space in print(' '.join(...) it displays as I showed up above! – José Rodrigues Sep 10 '19 at 16:12

score 1 · Answer 2 · answered Sep 10 '19 at 15:57

1

A great question! Here is my take on it without using any packages

def printH(nList):
    m = max(nList)
    while m > 0:
        for l in nList:
            if(l>=m):
                print('#',end = ' ')
            else:
                print(' ',end = ' ')
        print('')
        m-=1
num = [5,3,1,1,2]
printH(num)

Expected output:

#
#
# #
# #     #
# # # # #

answered Sep 10 '19 at 15:57

Harsha

353
1
15

I'm only comparing max value in the first pass of the loop (so the max height). In this pass: all columns with max height are printed with '#'. In the next run I'm checking it with max height -1 (refer to m-=1), this prints out all '#' with max height -1. This goes on until we reach m =0 (i.e., no more height). Try modifying my code by print(m) after 'for l in nList' so that you can track m. Let me know if this explanation does not make sense. – Harsha Sep 10 '19 at 16:23

Print a list of heights with "#" symbol

2 Answers2