GraphQL Where Select Sub Query

Question

These day, i have studied GraphQL with Laravel framework, Lighthouse Library. I have tried to do kind of SELECT Query.

As a result, I wonder GraphQL can select below SQL Query

SELECT * FROM TABLE_A WHERE type=1 AND chart_id=(SELECT id FROM TABLE_B WHERE phone='0000~~')

I expect, Client first get result from this query.

SELECT id FROM TABLE_B WHERE phone='0000~~'

And then Do Second query, i think i can get a result.

But i wonder I can get result from 1 request. Thanks.

@MikeRoss Yes. TableA has foreign key which name is chart_id. chart_id is the key of TableB — Jeongkuk Seo, Sep 03 '19 at 07:32

score 1 · Accepted Answer · answered Sep 03 '19 at 07:32

You can try following

 $phoneNumber = '0000~~';

 $data = DB::table('tableA')->where('type',1)
            ->whereIn('chart_id',function($query) use ($phoneNumber) {
                $query->select('id')
                      ->from('tableB')
                     ->where('phone', '=',$phoneNumber);
         })->get();

If there is relationship between tableA and tableB you can do following

 TableA::where('type',1)
        ->whereHas('tableBRelationshipName', function ($q) use ($phoneNumber) {
             $q->select('id')
             $q->where('phone','=',$phoneNumber);
 })->get();

GraphQL Where Select Sub Query

1 Answers1