How to get value from an array in PHP?

Question

This is the array result that I get from a function. I want to get the category_id from the array and only echo it.

{"categories": [{"parent_id": 15397, "has_children": true, "category_id": 15402, "category_name": "AC"}, {"parent_id": 0, "has_children": true, "category_id": 15397, "category_name": "A"}], "request_id": "3beac0674e937d2471e4b66b5f998976"}

after I json_decode my result, it shows like this.

stdClass Object ( [categories] => Array ( [0] => stdClass Object ( [parent_id] => 0 [has_children] => 1 [category_id] => 16 [category_name] => Women's Clothing ) [1] => stdClass Object ( [parent_id] => 16 [has_children] => 1 [category_id] => 1585 [category_name] => Dresses )

How to access the category_id when there is 2 stdclass object

//solved it
foreach ($arr as $obj => $arr) {
            foreach ($arr as $obj => $arr) {
                print_r($arr->category_id);

            }

        }

set second param in `json_decode()` to `true` so you will have it as an associative array — Moses Schwartz, Aug 23 '19 at 01:47
Possible duplicate of [json\_encode sparse PHP array as JSON array, not JSON object](https://stackoverflow.com/questions/11195692/json-encode-sparse-php-array-as-json-array-not-json-object) — LF00, Aug 23 '19 at 02:21

Adlan Arif Zakaria · Answer 1 · 2019-08-23T02:07:03.793

1

You don't actually need to have nested loop here because the first level is not array, but object.

$data = "{"categories": [{"parent_id": 15397, "has_children": true, "category_id": 15402, "category_name": "AC"}, {"parent_id": 0, "has_children": true, "category_id": 15397, "category_name": "A"}], "request_id": "3beac0674e937d2471e4b66b5f998976"}";

// Change to Array
$obj = json_decode($data, true);

// Get the data
foreach($obj['categories'] as $category) {
    print_r($category['category_id']);
}

edited Aug 23 '19 at 02:07

answered Aug 23 '19 at 01:58

Adlan Arif Zakaria

1,706
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Oh thank you, If i wanted to pass the category_id to another function, is it possible? – Tinagaran Aug 23 '19 at 02:03
Just call ```fnName($category['category_id'])``` to call a function like normal php do – Adlan Arif Zakaria Aug 23 '19 at 02:07

score 0 · Answer 2 · answered Aug 23 '19 at 02:28

<?php
 // Use this function to get the desired result, and then you can pass the result to another function
$data = '{"categories": [{"parent_id": 15397, "has_children": true, "category_id": 15402, "category_name": "AC"}, {"parent_id": 0, "has_children": true, "category_id": 15397, "category_name": "A"}], "request_id": "3beac0674e937d2471e4b66b5f998976"}';

function getCategoreIds($data=[]){
    $cids=[];
    $datas = json_decode($data,true);
    if($datas['categories']){
        foreach($datas['categories'] as $k=>$tmp){
            if(isset($tmp['category_id'])){
                $cids[] = $tmp['category_id'];
            }
        }
    }
    return $cids;
}

print_r(getCategoreIds($data));

How to get value from an array in PHP?

2 Answers2