convert scala parallel collection back to regular sequence

Question

How can a Parallel sequence:

Seq(1,2,3).par.map(_ +1)

be converted back to a regular sequence?

Seq(1,2,3).par.map(_ +1).reduce(_++_).toSeq

will not compile. There is an option of calling toArray though. But I believe there must be a better way returning back to a regular collection

I need to have a solution for 2.11.

At least until **2.12** there was a `.seq` method that would return the same collection, but sequentially. _(Anyways, I believe it still has to build a new collection, if that is what you want to avoid)_. — Luis Miguel Mejía Suárez, Aug 21 '19 at 15:04
Care to explain what you mean with that? - for **2.11** you can use the [`seq` method](https://www.scala-lang.org/api/2.11.11/index.html#scala.collection.parallel.ParIterable@seq:Sequential) as I said. — Luis Miguel Mejía Suárez, Aug 21 '19 at 15:08

vkt · Accepted Answer · 2019-08-21T15:12:54.920

5

Seq(1,2,3).par.map(_ +1).seq

edited Aug 21 '19 at 15:12

answered Aug 21 '19 at 15:06

vkt

1 Answers1