Combining FOR and IF in python

Question

Is there anyway to make this into a single statement in python ?

name = 'Customer_Identify'
useless_list = ['id']
# I Want to make the 3 following lines into a single line. It should return True.
for i in useless_list:
    if (i in name.lower()):
        print(True)

I tried with lambda functions but I maybe doing some mistake somewhere. :(

you might want a list comprehension like `filtered = [i for i in useless_list if i in name.lower()]` — Tom Dalton, Aug 19 '19 at 15:39
I suggest that you learn about list comprehensions and generator expressions — Code-Apprentice, Aug 19 '19 at 15:47
If you are only going to print, no need to change anything IMO... — Tomerikoo, Aug 19 '19 at 15:51
Your question is very unclear and hence different types of answers here. Do you want to return a single value, or print multiple times??? this changes the answers! — Tomerikoo, Aug 19 '19 at 15:56
If any one values in useless_list exists in the "name" the code must return True. else False. — JSVJ, Aug 19 '19 at 15:58
Well, that makes all but 1 answer here irrelevant... Try to be more clear in the question which by the way it is still not clear are you trying to print or return... everytime you say something else — Tomerikoo, Aug 19 '19 at 16:03
@Tomerikoo okay :) Thanks for your kind comments :) I will be clear from next time — JSVJ, Aug 19 '19 at 16:05

score 4 · Accepted Answer · answered Aug 19 '19 at 15:45

4

Since the question asked that it should return true. how about this ?

return any(i in name.lower() for i in useless_list)

answered Aug 19 '19 at 15:45

ruhaib

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Not sure that's the same functionality... Here you return/print one boolean value if any of the values are in name. In the OP, only `True` is printed **for each** value that is in name... – Tomerikoo Aug 19 '19 at 15:50
1

@Tomerikoo The comment in the OP's code states it wants to return the value, i just assume the print was used unintentionally perhaps ? – ruhaib Aug 19 '19 at 15:53
Oh didn't notice that comment and in that case I guess that satisfies the problem. It is indeed a little unclear... Actually, if that is really the intention I guess this is the best answer – Tomerikoo Aug 19 '19 at 15:54

Óscar López · Answer 2 · 2019-08-19T15:44:27.643

3

How about using generator expressions?

print('\n'.join(str(True) for i in useless_list if i in name.lower()))

edited Aug 19 '19 at 15:44

answered Aug 19 '19 at 15:40

Óscar López

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That's not a list anymore :) – Right leg Aug 19 '19 at 15:43
Oh! I see what you mean. Spot on, sir! – Óscar López Aug 19 '19 at 15:44
1

Another similar way without the use of `join` is unpacking with `print`'s extra arguments. Something like: `print(*(True for i in useless_list if i in name.lower()), sep='\n')` – Tomerikoo Aug 19 '19 at 16:00

score 0 · Answer 3 · answered Aug 19 '19 at 15:45

0

name = 'Customer_Identify'
useless_list = ['id', 'AA']

[print (item in name.lower()) for item in useless_list]

output:

True
False

answered Aug 19 '19 at 15:45

ncica

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score 0 · Answer 4 · answered Aug 19 '19 at 15:45

0

That's pretty awful, but you can use a list comprehension to actually invoke print:

[print(True) for i in useless_list if i in name.lower()]

Of course, that builds a totally useless list of Nones...

answered Aug 19 '19 at 15:45

Right leg

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Combining FOR and IF in python

4 Answers4