Django: Get generic view class from url name

Question

What's the recommended way of getting a generic view class from the url name?

url(r'^$', HomeView.as_view(), name='home')

So with 'home' I want to get the class HomeView.

You might want to go the other way round: from the view class' name to the url name. Why? Because class names are the more highly structured world. For instance, after a typo you will get a more meaningful error message if the offending line contains a name that does not resolve right there. (For class-based views, you would make a helper that applies `.as_view()` for you to make both the resolving and the notation simpler.) — Lutz Prechelt, Nov 14 '14 at 13:59

fmoor · Answer 1 · 2020-12-09T14:49:59.470

11

Django 1.9 introduced 2 attributes to the functions that as_view() returns. view_initkwargs and view_class.

Combining this with Pickles' answer:

from django.urls import reverse, resolve

url = reverse('home')
view = resolve(url).func.view_class

edited Dec 09 '20 at 14:49

answered Jun 22 '17 at 20:50

fmoor

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@IceFire, I added imports to the example. – fmoor Dec 09 '20 at 14:51

score 7 · Accepted Answer · edited May 23 '17 at 11:51

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The get_class I got from the following question: Does python have an equivalent to Java Class.forName()?

url = reverse('home')
resolver_match = resolve(url)
func = resolver_match.func
module = func.__module__
view_name = func.__name__

clss = get_class( '{0}.{1}'.format( module, view_name ) )

This is what I came up with myself I am very open to other answers.

edited May 23 '17 at 11:51

Community

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answered Apr 21 '11 at 19:53

Pickels

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I haven't found something better, but it's not completly satisfying because it is not exactly *fetching a view from its name*. The name is not enough to perform a call to `reverse` when the said url needs extra parameters (id for instance). – challet Dec 03 '20 at 14:19

score 6 · Answer 3 · answered Jan 23 '14 at 16:10

Inspired by Pickels' answer:

import importlib 
from django.core.urlresolvers import reverse, resolve

view_name = 'my_view_name'

view_func = resolve(reverse(view_name)).func
module = importlib.import_module(view_func.__module__)
view = getattr(module, view_func.__name__)

Django: Get generic view class from url name

3 Answers3