making sublist from sublist based on index position python

Question

I have a list

mainlist=[[1,2,3,4],['a','b','c','d'],[4,5,6,7]]

want to make sublist based on index position in sublist. The output is

finallist=[[1,'a',4],[2,'b',5],[3,'c',6],[4,'d',7]]

Thanks

complete duplicate (`zip(...)`) . Use search bar on SO – RomanPerekhrest Aug 13 '19 at 09:24 — RomanPerekhrest, Aug 13 '19 at 09:24
`print(list(map(list, zip(*mainlist))))` – Andrej Kesely Aug 13 '19 at 09:25 — Andrej Kesely, Aug 13 '19 at 09:25

score 1 · Accepted Answer · answered Aug 13 '19 at 09:26

1

Use zip with unpacking:

finallist = list(map(list, zip(*mainlist)))

answered Aug 13 '19 at 09:26

Austin

1 Answers1