How to escape double quote in parsley data-parsley-pattern?

Question

I am using parsley for javascript validation. My current regex pattern is

data-parsley-pattern="/^[0-9a-zA-Z\!\@\#\$\%\^\&\*\(\)\-\_\+\?\'\.\,\/\\r\n ]+$/"

How to add double quote in my pattern. I have added \" to pattern

data-parsley-pattern="/^[0-9a-zA-Z\!\@\#\$\%\^\&\*\(\)\-\_\+\?\'\"\.\,\/\\r\n ]+$/"

But it is not working.

Correct. See my answer. I hope it covers everything now. – Wiktor Stribiżew Aug 08 '19 at 12:46 — Wiktor Stribiżew, Aug 08 '19 at 12:46

Wiktor Stribiżew · Accepted Answer · 2019-08-08T12:48:11.223

Note that you overescaped the pattern, almost all the chars you escaped are not special in a character class.

Next, you may shorten the code if you use a string pattern. See Parseley docs:

data-parsley-pattern="\d+"

Note that patterns are anchored, i.e. must match the whole string. Parsley deviates from the standard for patterns looking like /pattern/{flag}; these are interpreted as literal regexp and are not anchored.

That means you do not need ^ and $ if you define the pattern without regex delimiters, /.

As for the quotation marks, you may use a common \xXX notation.

You may use

data-parsley-pattern="[0-9a-zA-Z!@#$%^&*()_+?\x27\x22.,/\r\n` -]+"

or

data-parsley-pattern="/^[0-9a-zA-Z!@#$%^&*()_+?\x27\x22.,/\r\n` -]+/$"

where \x27 is ' and \x22 is ".

Note that - at the end of the character class is a safe placement for a literal hyphen where you do not have to escape it.

Yes! now its working. Thank you very much. One doubt. can i use " symbol? — Pamba, Aug 08 '19 at 12:58
@srj Yes, `"` for `"` and `'` for `'`, too. I prefer the more generic `\xXX` notation, it is more portable across environments. — Wiktor Stribiżew, Aug 08 '19 at 12:58

How to escape double quote in parsley data-parsley-pattern?

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