How to simultaniously search for two possible quotation marks with regular expressions?

Question

I want to extract words in quotation marks if they are one or two words long. This works with the following Code.

mysentences = ['Kids, you "tried" your "best" and you failed miserably. The "lesson" is, "never try."', 
               "Just because I don’t 'care' doesn’t mean I don’t understand."]
quotation = []
rx = r'"((?:\w+[ .]*){1,2})"' 
for sentence in mysentences:
    quotation.append(re.findall(rx, sentence))
print(quotation)

But this doesn't get me the 'care' from the sencond sentence because the second sentence is in double quotation marks. I can get it with the following

r"'((?:\w+[ .]*){1,2})'"

The Question is, how can I join the conditions? with

rx = r'"((?:\w+[ .]*){1,2})"' or r"'((?:\w+[ .]*){1,2})'"

it only gets me the first mentioned condition.

[`"|'`](https://www.regular-expressions.info/alternation.html) — Olvin Roght, Aug 03 '19 at 13:15

The fourth bird · Accepted Answer · 2019-08-03T14:06:08.353

2

Using your current pattern, you could make use of a capturing group and a backreference \1 to match the accompanying single or double quote.

The match will now be in the second capturing group.

(['"])((?:\w+[ .]*){1,2})\1

Regex demo

Note that repeating the character class [ .]* could potentially also match for examplenever try... ....

If you want to match 1 or 2 words where there can be a single optional dot at the end, you could match 1+ word chars followed by an optional group to match 1+ spaces and 1+ word chars followed by an optional dot.

(['"])(\w+(?: +\w+)?\.?)\1

Regex demo

For example

import re
mysentences = ['Kids, you "tried" your "best" and you failed miserably. The "lesson" is, "never try."',
               "Just because I don’t 'care' doesn’t mean I don’t understand."]
quotation = []
rx = r"(['\"])((?:\w+[ .]*){1,2})\1"
for sentence in mysentences:
    for m in  re.findall(rx, sentence):
        quotation.append(m[1])

print(quotation)

Result

['tried', 'best', 'lesson', 'never try.', 'care']

edited Aug 03 '19 at 14:06

answered Aug 03 '19 at 13:23

The fourth bird

154,723
16
55
70

Unfortunately this also gives me the Quotation mark itself. I get [[('"', 'tried'), ('"', 'best'), ('"', 'lesson'), ('"', 'never try.')], [("'", 'care')]] – maybeyourneighour Aug 03 '19 at 13:45
1

@maybeyourneighour The matches are in the second capturing group. See for example https://ideone.com/Orekun – The fourth bird Aug 03 '19 at 13:58
@maybeyourneighour I have added an example to the answer getting the second value from the tuple that re.findall returns. – The fourth bird Aug 03 '19 at 14:06
Great! It works. But now I get one list for all sentences instead of one list for each sentence. – maybeyourneighour Aug 03 '19 at 15:22
1

@maybeyourneighour I see, do you mean like this? https://ideone.com/Ujmqxq – The fourth bird Aug 03 '19 at 15:26
1

Exactly! Thank you for your help – maybeyourneighour Aug 03 '19 at 15:27

How to simultaniously search for two possible quotation marks with regular expressions?

1 Answers1