python division with large numbers automatically ceiled

Question

Python 3.7.4 (tags/v3.7.4:e09359112e, Jul  8 2019, 19:29:22) [MSC v.1916 32 bit (Intel)] on win32
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>>> print(111111111111111111/10)
1.1111111111111112e+16
>>> print(int(111111111111111111/10))
11111111111111112
>>>

Refering to the above snippet, Can someone please help me understand why 111111111111111111/10 returns 11111111111111112 instead of 11111111111111111?

`11111111111111111.0 == 11111111111111112.0`. Floating point is wild. Use `//` for precise integer division, though. — Ry-, Jul 15 '19 at 07:51
@Ry- so i guess, `math.floor()` and others wont help as well in such cases? — thunderbird, Jul 15 '19 at 07:55
Correct. If you have two integers and want to divide them for an exact result, you have to use `//`. — Ry-, Jul 15 '19 at 08:54

score 3 · Accepted Answer · answered Jul 15 '19 at 07:51

3

Use floor division:

>>> 111111111111111111//10
11111111111111111
>>>

answered Jul 15 '19 at 07:51

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python division with large numbers automatically ceiled

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