seed = 5L in pyspark with Python 3 returns syntax error

Question

I am migrating to python 3, (from python 2)

seed = 5L
model = ALS.train(trainingRDD, rank, seed=seed, iterations=iterations,
                  lambda_=regularizationParameter)

and the first line of the code above returns invalid syntax error. How should I tune it in Python 3? The error is:

SyntaxError: invalid syntax
  File "<command-2039439267792266>", line 6
    seed = 5L
            ^
SyntaxError: invalid syntax

Thanks! I think the answer below is what you need then! Python 3 only has a single int type, they dropped the "long int" and combined. — mgrollins, Jul 12 '19 at 23:20
Possible duplicate of [Long Int literal - Invalid Syntax?](https://stackoverflow.com/questions/24249519/long-int-literal-invalid-syntax) — pault, Jul 15 '19 at 15:01

Giorgos Myrianthous · Accepted Answer · 2019-07-12T23:20:39.160

2

You just need remove L

seed = 5

Python 3.X integers support unlimited size in contrast to Python 2.X that has a separate type for long integers.

edited Jul 12 '19 at 23:20

answered Jul 12 '19 at 23:14

1 Answers1